{"id":2932,"date":"2020-10-31T08:17:00","date_gmt":"2020-10-31T08:17:00","guid":{"rendered":"http:\/\/onlineclassesguru.com\/?p=2932"},"modified":"2020-10-31T08:17:00","modified_gmt":"2020-10-31T08:17:00","slug":"chemistry-lab-report","status":"publish","type":"post","link":"https:\/\/onlineclassesguru.com\/index.php\/2020\/10\/31\/chemistry-lab-report\/","title":{"rendered":"Chemistry Lab Report"},"content":{"rendered":"<style type=\"text\/css\"><\/style><p><strong>YOU MUST SHOW ALL CALCULATIONS TO RECEIVE CREDIT FOR THEM! <\/strong><\/p>\n<table>\n<tbody>\n<tr>\n<td width=\"72\">gas<\/td>\n<td width=\"115\">color<\/td>\n<td width=\"134\">energy<\/p>\n<p>(E, eV)<\/td>\n<td width=\"134\">wavelenght<\/p>\n<p>(l, nm)<\/td>\n<td width=\"211\">1\/l\u00a0 (1\/nm)<\/td>\n<\/tr>\n<tr>\n<td width=\"72\">&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>H<sub>2<\/sub><\/td>\n<td width=\"115\">&nbsp;<\/p>\n<p>Blue-green<\/p>\n<p>Blue-green<\/p>\n<p>Orange<\/p>\n<p>Red<\/p>\n<p>&nbsp;<\/td>\n<td width=\"134\">&nbsp;<\/p>\n<p>2.30<\/p>\n<p>2.10<\/p>\n<p>2.00<\/p>\n<p>&nbsp;<\/td>\n<td width=\"134\">&nbsp;<\/p>\n<p>540<\/p>\n<p>580<\/p>\n<p>620<\/td>\n<td width=\"211\"><sup>\u00a0<\/sup><\/p>\n<p><sup>\u00a0<\/sup><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<table>\n<tbody>\n<tr>\n<td width=\"72\">&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>Ne<\/p>\n<p>&nbsp;<\/td>\n<td width=\"115\">&nbsp;<\/p>\n<p>Green<\/p>\n<p>Yellow<\/p>\n<p>Orange<\/p>\n<p>Red<\/td>\n<td width=\"134\"><strong>\u00a0<\/strong><\/p>\n<p>2.25<\/p>\n<p>2.14<\/p>\n<p>2.04<\/p>\n<p>1.90<\/td>\n<td width=\"134\"><strong>\u00a0<\/strong><\/p>\n<p>550<\/p>\n<p>580<\/p>\n<p>605<\/p>\n<p>650<\/p>\n<p>&nbsp;<\/td>\n<td width=\"211\"><sup>\u00a0<\/sup><\/td>\n<\/tr>\n<tr>\n<td width=\"72\">&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>Hg<\/p>\n<p>&nbsp;<\/td>\n<td width=\"115\">&nbsp;<\/p>\n<p>Purple<\/p>\n<p>Blue-Green<\/p>\n<p>Yellow<\/p>\n<p>Red<\/td>\n<td width=\"134\"><strong>\u00a0<\/strong><\/p>\n<p>2.85<\/p>\n<p>2.52<\/p>\n<p>2.14<\/p>\n<p>2.04<\/td>\n<td width=\"134\"><strong>\u00a0<\/strong><\/p>\n<p>435<\/p>\n<p>490.<\/p>\n<p>579<\/p>\n<p>607<\/td>\n<td width=\"211\"><strong>\u00a0<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p>Calculations:<\/p>\n<p>&nbsp;<\/p>\n<ul>\n<li>Prepare a plot of energy vs. (1\/wavelength) for Hg, H<sub>2<\/sub> and Ne graph by using excel.<\/li>\n<li>Calculate slope of the best fit line for each gas, show your calculations in your lab report sheet, computer calculated answer will not be accepted.<\/li>\n<li>\n<ul>\n<li>Calculate the Planck\u2019s constant for each gas by using the slope from each graph and following the example shown in the lab manual.<\/li>\n<\/ul>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>Example calculation of slope from Hg graph:<\/strong><\/p>\n<p>X<sub>1<\/sub> = 1.83 x 10<sup>-3 <\/sup>\u00a0y<sub>1<\/sub>= 2.30 eV<\/p>\n<p>X<sub>2<\/sub> = 2.20 x 10<sup>-3 <\/sup>\u00a0y<sub>2<\/sub>= 2.70 eV<\/p>\n<p><u>Y<sub>2<\/sub>-Y<sub>1 <\/sub>\u00a0<\/u>\u00a0= <u>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02.70 eV\u2013 2.30 eV\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/u>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0=\u00a0 1066.7eV nm<\/p>\n<p>X<sub>2<\/sub>-X<sub>1<\/sub> \u00a0\u00a0\u00a0\u00a0(2.20 x 10<sup>-3 <\/sup>nm<sup>-1<\/sup>) \u2013 (1.83 x 10<sup>-3<\/sup> nm<sup>-1<\/sup>)<\/p>\n<p>&nbsp;<\/p>\n<p>Unit conversions:<\/p>\n<p>1067 eV nm\u00a0 x\u00a0 <u>1.00 x 10<sup>-9<\/sup> m <\/u>\u00a0x\u00a0 <u>1.602 x 10<sup>-19<\/sup> J <\/u>\u00a0= 1.71 x 10<sup>-25 <\/sup>Jm<\/p>\n<p>1nm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1 eV<\/p>\n<p>h = slope\/c = <u>1.71 x 10<sup>-25 <\/sup>Jm\u00a0\u00a0 <\/u>\u00a0= 5.70 x 10<sup>-34<\/sup> Js<\/li>\n<li>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2.998 x 10<sup>8<\/sup> ms<sup>-1<\/sup>\n<p>&nbsp;<\/p>\n<p><strong>Calculations and Excel Graphs <\/strong>(you can use as much space as needed):<\/p>\n<p><strong>Discussion questions<\/strong><\/p>\n<p>&nbsp;<\/p>\n<ol>\n<li>Show the calculation of Planck\u2019s constant, mentioned in calculations #3 (in your book, page #61, printed version), including the unit conversion for mercury, hydrogen and neon.&nbsp;\n<ol>\n<li>Using Equations 1 and 2 from the introduction (page 57 in lab manual, printed version), derive the equation that will allow you to find Planck\u2019s constant from your graph.<\/li>\n<\/ol>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p>&nbsp;<\/p>\n<ol start=\"2\">\n<li>Average all of the calculated values of Planck\u2019s constants you obtained. Calculate the percent error of this value compared to the accepted value of Planck\u2019s constant.<\/li>\n<\/ol>\n<p><strong>\u00a0<\/strong><\/p>\n<ol>\n<li>Compare the averaged value of Planck\u2019s constant determined in discussion questions 3 to the accepted value of Plank\u2019s constant. Did you obtain a value of Planck\u2019s constant that was within \u00b110% of the literature value? If not, explain why. Does averaging many experimental observations create a more accurate constant? Explain.<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<\/li>\n<\/ul>\n<p><center><a href=\"http:\/\/onlineclassesguru.com\/orders\/ordernow\"><img decoding=\"async\" src=\"https:\/\/encrypted-tbn0.gstatic.com\/images?q=tbn:ANd9GcTyj99p60XCLyLk1htB7-1neRt8-2QdnenNlQ&usqp=CAU\"target=\"_http:\/\/onlineclassesguru.com\/orders\/ordernow\"\/><\/center><p>","protected":false},"excerpt":{"rendered":"<p>YOU MUST SHOW ALL CALCULATIONS TO RECEIVE CREDIT FOR THEM! gas color energy (E, eV) wavelenght (l, nm) 1\/l\u00a0 (1\/nm) &nbsp; &nbsp; H2 &nbsp; Blue-green Blue-green Orange Red &nbsp; &nbsp; 2.30 2.10 2.00 &nbsp; &nbsp; 540 580 620 \u00a0 \u00a0 &nbsp; &nbsp; Ne &nbsp; &nbsp; Green Yellow Orange Red \u00a0 2.25 2.14 2.04 1.90 \u00a0&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-2932","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Chemistry Lab Report - onlineclassesguru<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/onlineclassesguru.com\/index.php\/2020\/10\/31\/chemistry-lab-report\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Chemistry Lab Report - onlineclassesguru\" \/>\n<meta property=\"og:description\" content=\"YOU MUST SHOW ALL CALCULATIONS TO RECEIVE CREDIT FOR THEM! 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